On 10/30/13, John Regehr <regehr_at_[hidden]> wrote:
>> void print_type( int arg )
>> { std::cout << "unsigned" << std::endl; }
>> void print_type( unsigned int arg )
>> { std::cout << "signed" << std::endl; }
>
> Wait a sec, each of these is printing the opposite of what it's supposed
> to print, right?

Oh, sorry, transcription error. At any event, in in my mind, the unexpected
thing happens. (Unexpected from the user view, not from the standards view.)

-- 
Lawrence Crowl