On 16 October 2013 18:46, Gabriel Dos Reis <gdr_at_[hidden]> wrote:

>
> | My own personal view (not that of chair) is that if
> std::less<T>(l,r) and
> | "l < r" are
> | both defined, then they should yield the same answer.
> |
> |
> | Which fails for pointers.
>
> "fails" in which sense? It is certainly true in the current standards
> these expressions are both defined when 'l' and 'r' are related
> addresses (relative to the same object), which was exactly my point.
>
>
>
Fails in the sense that less<int*>(l, r) and l<r do not necessarily yield
the
same answer.