Then why not call the respective f() functions from the constructors? -----Ursprüngliche Nachricht----- Von:Rainer Deyke via Std-Proposals <std-proposals_at_[hidden]> Gesendet:Mi 01.07.2026 08:26 Betreff:Re: [std-proposals] c++ proposal An:std-proposals_at_[hidden]; CC:Rainer Deyke <rainerd_at_[hidden]>; On 7/1/26 08:12, Sebastian Wittmeier via Std-Proposals wrote: > Making f() virtual is a bit confusing: > > > During construction only the base member function is called. So it could be non-virtual as well? Making f() virtual is the whole point of the example. When called from base::base, base::init calls base::f. When called from derived1::dervived1, base::init calls derived1::f. When called from derived2::dervived2, base::init calls derived2::f. -- Rainer Deyke - rainerd_at_[hidden] -- Std-Proposals mailing list Std-Proposals_at_[hidden] https://lists.isocpp.org/mailman/listinfo.cgi/std-proposals