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Should the constructor of std::reference_wrapper be explicit?

From: Vladimir Grigoriev <vlad.moscow_at_[hidden]>
Date: Fri, 26 Mar 2021 21:32:43 +0300
Consider the following code snippet.
    int x = 10;
    std::reference_wrapper<int> rx( x );
    std::swap( rx, x );
The compiler will issue an error because either rx can be implicitly converted to the type int or x can be implicitly converted to the type std::reference_wrapper<int>.
So a pair of questions are arising.
Should the constructor of the class template std::reference_wrapper be explicit?
What is the reason that the constructor is implicit? Is that so necessary?
You can meet me at http://cpp.forum24.ru/ or www.stackoverflow.com or http://ru.stackoverflow.com

Received on 2021-03-26 13:32:49