No, an object whose type is your aggregate class C has only two elements:
the base class subobject of type B and the member named z. Likewise, the
initializer-list which initializes c contains two elements: the first is
the initializer-list "{ { .x = 10 }, 20 }" and the second is the
literal 30. Since one of those initializers happens to itself be an inner
initializer-list and the element is also an aggregate type, the
list-initialization process happens recursively to initialize the elements
of the B subobject, then to initialize the element of the A subobject. A
note in [decl.init.aggr] paragraph (4.2) notes that exactly this sort of
semantic recursion can happen.

(Paragraph 15 explains how and when braces around elements of a
subaggregate's initializer can sometimes be elided, but this is still all
in terms of a direct base class, not an indirect base class, being an
aggregate member.)

-- Andrew Schepler


On Fri, Nov 15, 2019 at 8:00 AM Vladimir Grigoriev via Std-Discussion <
std-discussion_at_[hidden]> wrote:

> The following phrase from the C++ Standard (9.3.1 Aggregates, p. #2)
> confuses
>
> 2 The elements of an aggregate are:
> (2.2) — for a class, the direct base classes in declaration order,
> followed by the direct non-static data members (11.3) that are not members
> of an anonymous union, in declaration order.
>
> Should is there the word "recursively" be inserted somewhere in the
> phrase relative to the direct base classes?
>
> This would make for example this initialization more clear
>
> #include <iostream>
>
> struct A
> {
> int x;
> };
>
> struct B : A
> {
> int y;
> };
>
> struct C : B
> {
> int z;
> };
>
> int main()
> {
> C c = { { { .x = 10 }, 20 }, 30 };
>
> std::cout << "c.x = " << c.x << ", " << "c.y = " << c.y << ", c.z = " <<
> c.z << '\n';
> }
>
>
> With best regards,
>
> Vlad from Moscow
>
> You can meet me at http://cpp.forum24.ru/ or www.stackoverflow.com or
> http://ru.stackoverflow.com
> --
> Std-Discussion mailing list
> Std-Discussion_at_[hidden]
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>