On Tuesday, June 2, 2026, Thiago Macieira wrote:

>
>
> There is only one symbolic operator added to C++ since its inception, and
> that's the spaceship one.
>


The number one most convenient unary operator we could add to the language
would be for 'std::forward'. So if you write:

    ?var

then it's the same as:

    (decltype(var)&&)var

with a compulsory compiler warning/error if 'var' is not a function
parameter forwarding reference.