Because pointer IS a optional reference by semantic

пн, 20 нояб. 2023 г. в 04:32, Magnus Fromreide via Std-Proposals <
std-proposals_at_[hidden]>:

> Hello!
>
> When I saw the failable API's the first question I asked myself was why you
> choose to use T* as return type rather than
> std::optional<std::reference_wrapper<T>> or possibly
> std::expected<std::reference_wrapper<T>, void>
>
> /MF
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