Subject: Re: [ub] Justification for < not being a total order on pointers?
From: Nevin Liber (nevin_at_[hidden])
Date: 2013-08-26 11:12:15
On 26 August 2013 11:00, Jeffrey Yasskin <jyasskin_at_[hidden]> wrote:
> Could someone explain why we need to allow operator<(T*) to be a non-order?
It comes from C. I believe it comes from the days of segmented
I do not know of any modern machines that have such architectures and have
C++11 compilers for them. Whenever it comes up for discussion on various
reflectors, no one has mentioned one either. I for one would like to see
this restriction go away.
Armchair thought: maybe we should propose a total ordering for pointers
(for C++17 at this point) and see if anyone objects?
All that being said, I believe Library is inconsistent in its use of
operator< vs. std::less<T>, and that needs to be addressed separately.
Pointers are the current poster child for the issue but user code might be
specializing std::less as well.
-- Nevin ":-)" Liber <mailto:nevin_at_[hidden]> (847) 691-1404
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