If something has at least (>=) 8 bits, then it can also have e.g. 16 bits? Even if bytes are 8 bits? -----Ursprüngliche Nachricht----- Von:Thiago Macieira via Std-Proposals <std-proposals_at_[hidden]> Though if the CHAR_BIT == 8 paper gets adopted, then uint_least8_t becomes obsolete: the type that has at least 8 bits is the type that has exactly 8 bits.