Sorry if my previous reply went through - either way you still need the
continue in the while loop.

On Thu, Nov 9, 2023 at 5:16 PM sasho648 <sasho648_at_[hidden]> wrote:

> Do:
>
> for ( ; ; ++p )
> while(SerialSimGsm.available())
> {
> if ( p >= &buf[sizeof(buf) - 1u] ) break;
> p[0u] = SerialSimGsm.read();
> p[1u] = '\0';
> unsigned const len = std::strlen(buf);
> char *ending = nullptr;
> if ( nullptr != (ending = std::strstr(buf, "\r\n")) )
> {
> ending[0u] = '\0';
> ending[1u] = '\0'; // Overwrite the "\r\n" with "\0\0"
> if ( ending != buf ) this->ProcessInput();
> buf[0u] = '\0';
> p = buf;
> continue;
> }
> break;
> }
>
> On Thu, Nov 9, 2023 at 5:10 PM sasho648 <sasho648_at_[hidden]> wrote:
>
>> Yeah that's fair - didn't think this through - well just don't use for
>> then.
>>
>> On Thu, Nov 9, 2023 at 2:24 PM Frederick Virchanza Gotham via
>> Std-Proposals <std-proposals_at_[hidden]> wrote:
>>
>>> On Tue, Nov 7, 2023 at 12:14 PM sasho648 wrote:
>>> >
>>> > Anyone mentioned goto? - With goto you can do exactly what the OP is
>>> asking for:
>>> >
>>> > for ( ; SerialSimGsm.available(); ++p )
>>> > rev_con:
>>> > {
>>> > if ( p >= &buf[sizeof(buf) - 1u] ) break;
>>> > p[0u] = SerialSimGsm.read();
>>> > p[1u] = '\0';
>>> > unsigned const len = std::strlen(buf);
>>> > char *ending = nullptr;
>>> > if ( nullptr != (ending = std::strstr(buf, "\r\n")) )
>>> > {
>>> > ending[0u] = '\0';
>>> > ending[1u] = '\0'; // Overwrite the "\r\n" with
>>> "\0\0"
>>> > if ( ending != buf ) this->ProcessInput();
>>> > buf[0u] = '\0';
>>> > p = buf;
>>> > goto rev_con; // Don't allow 'p' to be incremented
>>> > }
>>> > }
>>>
>>>
>>>
>>> Your strategy causes an assertion failure in my code:
>>>
>>> https://godbolt.org/z/v6Px1Tao4
>>>
>>> because your 'goto' is skipping the pre-iterative condition check.
>>>
>>> Perhaps there should be four ways of continuing a loop:
>>>
>>> continue; // Don't skip anything
>>> continue(skip post); // Skip the post-iterative step
>>> continue(skip pre); // Skip the pre-iterative condition
>>> check
>>> continue(skip both); // Skip both the post-iterative
>>> step and the pre-iterative condition check
>>>
>>> The four words 'skip, pre, post, both' would not be keywords in the
>>> C++ language, but would be words with special meaning only when
>>> encountered in parentheses following 'continue'.
>>> --
>>> Std-Proposals mailing list
>>> Std-Proposals_at_[hidden]
>>> https://lists.isocpp.org/mailman/listinfo.cgi/std-proposals
>>>
>>