Also to have an equivalent floating-point interface that can actually
generate both 1.0 and 0.0

On Wed, Mar 3, 2021 at 3:02 PM Edward Catmur <ecatmur_at_[hidden]> wrote:

> It seems to me that what you really want is a uniform_int_distribution
> that accepts a half-open interval. I assume the reason the Standard
> specifies a closed interval is to allow a distribution over the whole of an
> integer type?
>
> On Wed, Mar 3, 2021 at 9:59 AM Gašper Ažman via Std-Proposals <
> std-proposals_at_[hidden]> wrote:
>
>> Not sure if I understand, because it seems so obvious otherwise: you just
>> want a function that returns size()-1?
>>
>> On Wed, Mar 3, 2021 at 7:56 AM Kurt Raburn via Std-Proposals <
>> std-proposals_at_[hidden]> wrote:
>>
>>> hello,
>>>
>>> i'm not sure if this was my fault, but this is the issue i was having.
>>>
>>> std::uniform_int_distribution<int> dist(0, vec.size()); // runtime error
>>>
>>> std::uniform_int_distribution<int> dist(0, vec.size() - 1); // ok
>>>
>>> after some thought, i wrote a function that returns the index count.
>>>
>>> template<typename T>
>>> int indices(const std::vector<T>& vec)
>>> {
>>> int cnt = 0;
>>>
>>> for (T i : vec) {
>>> ++cnt;
>>> }
>>>
>>> return --cnt;
>>> }
>>>
>>> then, i modified the size() function, and it returned the same result.
>>>
>>> _NODISCARD size_type indices() const noexcept
>>> {
>>> return (static_cast<size_type>(this->_Mylast() -
>>> this->_Myfirst() - 1));
>>> }
>>>
>>> usage:
>>>
>>> std::uniform_int_distribution<int> dist(0, vec.indices());
>>>
>>> forgive me if i overlooked a library function that would've solved this.
>>>
>>>
>>>
>>>
>>>
>>> --
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>>> Std-Proposals_at_[hidden]
>>> https://lists.isocpp.org/mailman/listinfo.cgi/std-proposals
>>>
>> --
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>>
>