Not sure if I understand, because it seems so obvious otherwise: you just
want a function that returns size()-1?

On Wed, Mar 3, 2021 at 7:56 AM Kurt Raburn via Std-Proposals <
std-proposals_at_[hidden]> wrote:

> hello,
>
> i'm not sure if this was my fault, but this is the issue i was having.
>
> std::uniform_int_distribution<int> dist(0, vec.size()); // runtime error
>
> std::uniform_int_distribution<int> dist(0, vec.size() - 1); // ok
>
> after some thought, i wrote a function that returns the index count.
>
> template<typename T>
> int indices(const std::vector<T>& vec)
> {
> int cnt = 0;
>
> for (T i : vec) {
> ++cnt;
> }
>
> return --cnt;
> }
>
> then, i modified the size() function, and it returned the same result.
>
> _NODISCARD size_type indices() const noexcept
> {
> return (static_cast<size_type>(this->_Mylast() - this->_Myfirst()
> - 1));
> }
>
> usage:
>
> std::uniform_int_distribution<int> dist(0, vec.indices());
>
> forgive me if i overlooked a library function that would've solved this.
>
>
>
>
>
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>