Subject: Re: [std-proposals] std::nabs (negative abs) idea
From: Brian Bi (bbi5291_at_[hidden])
Date: 2021-02-12 10:58:43
What are the use cases for this function?
I guess a potentially overflowing `x + abs(y)` could be replaced by `x -
nabs(y)`, but the overall result could still overflow...
On Fri, Feb 12, 2021 at 11:37 AM Andrey Semashev via Std-Proposals <
> I've been contemplating a possible new standard function std::nabs,
> which would return a negated absolute value of its argument:
> assert(std::nabs(1) == -1);
> assert(std::nabs(-1) == -1);
> assert(std::nabs(0) == 0);
> The idea behind this addition is that, unlike std::abs, this function
> will never cause a signed integer overflow. This is because in two's
> complement representation, which is mandatory since C++20, any positive
> integer can be negated without overflow, but not vise versa.
> I wonder if this idea has come up before.
> Std-Proposals mailing list
-- *Brian Bi*
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