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Re: [ub] Aliasing char16_t with int_least16_t, etc.

From: Daniel Krügler <daniel.kruegler_at_[hidden]>
Date: Fri, 1 Nov 2013 11:55:56 +0100
2013/11/1 Lawrence Crowl <Lawrence_at_[hidden]>:
> On 10/31/13, Jean-Marc Bourguet <jm_at_[hidden]> wrote:
>> On 31/10/2013 01:28, Lawrence Crowl wrote:
>>> On 10/30/13, Jean-Marc Bourguet <jm_at_[hidden]> wrote:
>>>> Does 3.10/10 covers the puning between uint_leastXX_t and
>>>> int_leastXX_t?
>>> I believe so, because those are just typedefs and they are
>>> required to point to the same size.
>> Are you sure? I though it was a requirement on value bits and
>> thus the typedef could be on the next size.
>> A machine similar to the unysis described by Ion which has to
>> ignore the sign type in unsigned instead of making it contribute
>> to the value could have a 16 bits type whose unsigned correspondent
>> has a max of 2^15-1. If I'm not mistaken, it would have to be
>> used as int_least16_t but the unsigned can't be used as
>> uint_least16_t.
>> (That type has to be an extended integer as USHRT_MAX has to be at
>> least 65535 and unsigned char can't have padding bits).
> Reading the C standard, there does not seem to be any requirement
> that uint* typedefs have the same size as the corresponding int*
> typedefs.

I disagree. According to C99 7.18.1 p1:

"When typedef names differing only in the absence or presence of the
initial u are defined,
they shall denote corresponding signed and unsigned types as described
in 6.2.5; an
implementation providing one of these corresponding types shall also
provide the other."

and 6.2.5 p6 defines "corresponding signed and unsigned types":

"For each of the signed integer types, there is a corresponding (but
different) unsigned
integer type (designated with the keyword unsigned) that uses the same amount of
storage (including sign information) and has the same alignment requirements."

> However, the unsigned X types must be the same size as
> the signed X types to match the aliasing rules. So, I suspect that
> if uint_least16_t were not the same size as int_least16_t there would
> be some program breakage.

Yes and it what not be a conforming implementation, see above.

- Daniel

Received on 2013-11-01 11:56:10