Perhaps

template <typename T>

std::tuple<std::complex<T>,std::complex<T>,std::complex<T> > cbrt (std::complex<T> const &c)

?

On Tue, Oct 25, 2022 at 11:48 AM Dejan Milosavljevic <dmilos@gmail.com> wrote:

Cubic root have three solutions.What is the rule to uniquely pick the first one?

Rest of them we can have by multiply with cbrt( {+1,0} );

My proposal for complex cbrt:

template< typename T/*number like*/>

std::complex<T> cbrt( std::complex<T> const& c, int index =0 /* which root to use is defined by ( index % 3) 0,1 or 2 */ );

This might be too complex.

Any idea to make it simple?On Tue, Oct 25, 2022 at 5:01 PM Jason C via Std-Proposals <std-proposals@lists.isocpp.org> wrote:<complex> is conspicuously missing cbrt().--If I put together a proposal to add std::cbrt(std::complex) to <complex>, would there be any interest?Any thoughts?Jason

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