You're correct, std::construct should be a variable template with one parameter.

Regarding make_obj vs std::construct, obj is not a word, and I think the standard should try hard to use words. I think std::construct is consistent with std::construct_at.

btw are make_obj_using_allocator and std::construct related? The former allocates, the latter does not.

On Sun, 2025-05-11 at 12:38 -0400, Arthur O'Dwyer wrote:
Hi Avi,

FWIW, I'm not sure P3312 is going anywhere; notice it's still in EWGI, and the syntax/semantics proposed don't seem very C++-ish to me.
OTOH, your `std::construct` as written is very similar to the existing `std::make_obj_using_allocator`; the only difference is that make_obj_using_allocator takes a first argument of type std::allocator<T>, whereas yours omits that parameter.
OTOOH, your `std::construct` definitely doesn't achieve your purpose as written. You wrote a template of 1+K parameters, and then instantiated it with 1+0 arguments: 
https://godbolt.org/z/8dnqThW1Y

template<class T, class... Args>
T std_construct(Args&&... args) {
  return T(std::forward<Args>(args)...);
}

struct Arg1 {} arg1;
struct Arg2 {} arg2;
struct Arg3 {} arg3;
struct Type1 {
  explicit Type1(Arg1, Arg2&, Arg3);
};

This code allows you to write:

Type1 (*pf3)(Arg1&&, Arg2&, Arg3&&) = std_construct<Type1, Arg1, Arg2&, Arg3>;

But it certainly does not allow you to write either:

Type1 (*pf0)() = std_construct<Type1>;  // no, Type1 has no zero-argument constructor
Type1 (*pf3)(Arg1, Arg2&, Arg3) = std_construct<Type1>;  // no, Typ1 has no zero-argument constructor and pf3 doesn't have the same function type as the zero-argument std_construct<Type1>
auto make_something = std::bind_front(std_construct<Type1>, ~~~); // certainly not

What you need for a generic-lambda-style thing is for std::construct<T> to be a callable object in its own right, like this:
https://godbolt.org/z/TTbf6cGdx

All Ranges adaptors are "partially applied templates" similar to what we're doing here.
Should make_obj_using_allocator be a "partially applicable" template like this, instead of a "fully applicable only" template as it currently is?

Should there be a new "partially applicable" template named std::make_obj and/or std::construct? (I would prefer the former name, FWIW, for consistency.)

Should there be a new core-language feature that permits automatic handling of the "partial application" of templates, somehow?
(But this last would run into trouble with backward compatibility, because your `std::construct<Type1>` from above is already legal C++ today: it just unambiguously does something different from what you want it to do. Making it automatically represent a "partial but not complete specification" of std::construct's template parameter list would change its meaning, possibly changing the meaning of existing code.)

my $.02,
–Arthur


On Sun, May 11, 2025 at 7:37 AM Avi Kivity via Std-Proposals <std-proposals@lists.isocpp.org> wrote:
This is superceded by P3312 [1].
Instead of std::construct<T>(...), write (&T::T)(...).

On Sun, 2024-12-01 at 17:57 +0200, Avi Kivity wrote:
Functions and member functions are invocable, but constructors are not.

I propose to add

template <typename T, typename... Args>
T std::construct(Args&&... args) {
    return T(std::forward<decltype(Args)>(args)...);
}

With this, we can pass a constructor where other functions can be
passed.

    // build a callback that creates and returns a Type1 thing
    std::function<Type1 (Arg3)> make_somthing =
std::bind_front(std::construct<Type1>, arg1, std::ref(arg2));

    // transform a vector of ints to a vector of some other type
    auto foo = some_container |
std::views::transform(std::construct<AnotherType>) |
std::ranges::to<std::vector>();