If what you say were true, then the following would also be a forwarding reference:

    template<typename T>

    void Func( array<T, 8u> &&arg ) { }

But it's not. It'a actually just an Rvalue reference, and 'arg' will never be an Lvalue.

It also ceases to be a forwarding reference if you throw in a CV qualifier of any kind:

    template<typename T>

    void Func( T volatile &&arg ) { }

So if you have a template function with a template type of T, and a function parameter of type 'T&&', then the '&&' doesn't mean Rvalue reference. It means 'forwarding reference', and it is horrid. They should have went with:

    template<typename T>

    void Func( T LorR arg ) { }

or perhaps even:

    template<typename T>

    void Func( T & || && arg ) { }