Also is

auto z1 = i + u;

auto z2 = u + i;

the same type?
 

-----Ursprüngliche Nachricht-----
Von: Howard Hinnant via Std-Proposals <std-proposals@lists.isocpp.org>

Assume char is 8 bit, short is 16 bit, int is 32 bit

 

signed char i{};

unsigned char u{};

 

auto z = i + u;

 

Possibilities:

 

compile-time error

run-time error

z is signed char

z is unsigned char

z is short

z is unsigned short

z is int

z is unsigned int

 

What is your recommendation?

 

Howard