Hello Gents,

    Given this case:

*****

// primary template 

template<void(*)(int)>

struct A;

// specialization 

template<typename T, typename V

    ,template<typename, typename> F

    ,void (*(F<T,V>)(int)>

struct A<F> { };

******

Why this specialization doesn't compile?

And how to extract the template params of a function template, let say

template<typename T, typename V>

void foo(int) {};

In a templated struct that accepts function pointers, let say

template<void(*)(int)>

struct A { // impl };

Regards 

Nadir