I sometimes intuitively write something along the lines:

if (std::any_of(begin(v), end(v))) { }

where v is a container of bools or something similar. And when I compile my code, reality hits. The std::any_of, std::all_of and std::none_of algorithms can only be called with a predicate as third argument.

So I need to write

if (std::any_of(begin(v), end(v), [](auto e) { return e; })) { }

Or in C++20 I might be able to use std::identity. Still, the third argument feels unnecessary to me.

This has been discussed before here: https://groups.google.com/a/isocpp.org/forum/#!searchin/std-proposals/all_of|sort:date/std-proposals/sKA_dDQiU_g/OTDMnQ7fBwAJ

But the discussion quickly went off into various different proposals.

Is there a compelling reason, why std::any_of, std::all_of and std::none_of do not have an overload without a predicate and just convert the elements of the passed range to bool?

It feels like an oversight to me. Or maybe the use case is just too small?

Anyway, thank you for the feedback!