For int i = 0; const i; std::cout << &i << std::endl; Would the compiler be allowed to optimize out the non-const phase of i and put it into read-only-memory? For int i = 0; std::cout << &i << std::endl; const i; std::cout << &i << std::endl; Would the compiler be allowed to relocate i between non-const memory and read-only-memory and print out two different addresses?