On Sun, Jan 26, 2025 at 11:17 PM Jeremy Rifkin wrote:
>
> > For example on a system where CHAR_BIT==8 but the smallest addressable unit of memory is 16 bits
>
> That's not possible https://eel.is/c++draft/basic.memobj#intro.memory-1


It's possible if the compiler hides it from the programmer. For
instance if CHAR_BIT==8, and if the CPU instructions deal with 16-Bit
operands, then you can have:

    CHAR_BIT == 8
    sizeof(int*) == 2
    sizeof(char*) == 3

An int* is a 16-Bit number representing a memory address.
A char* is a 16-Bit number representing a memory address, with an
extra byte to indicate the offset.