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Re: [std-proposals] Use optional<T> as though it were T

From: Giuseppe D'Angelo <giuseppe.dangelo_at_[hidden]>
Date: Sun, 25 Jun 2023 14:42:00 +0200
Il 25/06/23 13:53, Frederick Virchanza Gotham via Std-Proposals ha scritto:
> Of course this would mean that you need to edit the code everywhere so
> that you have "g_obj->" instead of "g_obj.", unless of course you were
> to do:
> optional<T> g_optional_obj;
> T &g_obj = *g_optional_obj.operator->();
> Strictly speaking this is undefined behaviour but it will work fine so
> long as you make sure to 'emplace' the object before using 'g_obj'.

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Giuseppe D'Angelo | giuseppe.dangelo_at_[hidden] | Senior Software Engineer
KDAB (France) S.A.S., a KDAB Group company
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Received on 2023-06-25 12:42:03