On 1/7/23 03:35, Peter Olsson via Std-Proposals wrote:
>> a.foo(move(list<int>{0, 1, 2, 3, 4, 5, 6, 7, 8, 9}));
>
>> foo(move(ostream()));
>
> Do you realize that using std::move on a temporary like this is pretty
> pointless because it's already an rvalue?

I was referring to the automatic generated code by the source-to-source
compiler. Whether it's a r-value and l-value, a move() will be generated.

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