Cubic root have three solutions.
*What is the rule to uniquely pick the first one?*
Rest of them we can have by multiply with cbrt( {+1,0} );

My proposal for complex cbrt:
 template< typename T/*number like*/>
  std::complex<T> cbrt( std::complex<T> const& c, int index =0 /* which
root to use is defined by ( index % 3) 0,1 or 2 */ );

This might be too complex.
Any idea to make it simple?

On Tue, Oct 25, 2022 at 5:01 PM Jason C via Std-Proposals <
std-proposals_at_[hidden]> wrote:

> <complex> is conspicuously missing cbrt().
>
> If I put together a proposal to add std::cbrt(std::complex) to <complex>,
> would there be any interest?
>
> Any thoughts?
>
> Jason
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