On 05/03/2020 06.29, J Decker via Std-Proposals wrote:
> Smart pointers continue to work as they do, because they are an object that
> contains a pointer to an object, and are not 'pointers'. they are of a
> class type 'smart pointer', they are not pointers to a class of type 'smart
> pointer'.

So... now when I go to refactor my code, replacing a raw pointer with a
smart pointer, my code now breaks, or worse, silently changes behavior?

No, thanks.

-- 
Matthew