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Re: count-based for loop

From: Sophia Poirier <spoirier_at_[hidden]>
Date: Tue, 27 Aug 2019 10:42:15 -0700
> On Aug 27, 2019, at 10:26 AM, Barry Revzin <barry.revzin_at_[hidden]> wrote:
>
>> On Tue, Aug 27, 2019, 12:02 PM Sophia Poirier via Std-Proposals <std-proposals_at_[hidden]> wrote:
>> Thanks, yes I have that as an alternate example in my longer notes. My understanding is that it still suffers from the type-matching problem as traditional for loops. Your example of:
>>
>> for (const auto i : std::views::iota(0, count))
>>
>> only works when count is an int. Otherwise, if for example count is uint32_t, it would need to be:
>>
>> for (const auto i : std::views::iota(uint32_t{0}, count)
>> or:
>> for (const auto i : std::views::iota(0u, count))
>> or:
>> for (const auto i : std::views::iota<uint32_t>(0, count))
>> or:
>> for (const auto i : std::views::iota<decltype(count)>(0, count))
>>
>> or something along those lines, or you will get template instantiation failure compiler error. I think that if std::views::iota had a constructor overload that was simply the second argument (count) with implicit zero start, then it would be a good option. However I believe there is interest to reserve such an overload perhaps for infinite ranges?
>>
>> thanks,
>> Sophia
>
>
> This is true. But we can write a helper function to get the correct type of 0 so we don't need the ugliness at point of use:
>
> template <std::integral T>
> auto upto(T n) {
> return views::iota(T{0}, n);
> }
>
> We end up with:
>
> for (const auto i : upto(count))
>
> Barry

This could be the basis of an alternate library proposal, true.

- Sophia

Received on 2019-08-27 12:44:27