Hello,

With <iostream> int8_t prints out char according to ascii number. Similarly it reads a single char, which cannot be static int converted. The compiler gives no warning whatsoever. But when <cstdio> is used with scanf %hhd and printf %d it works perfectly. Is this really the intended <iostream> functioning? In Rust i8 and C <stdio.h> int8 works fine, too.

#include <iostream>

#include <cstdint>

int main()

{

std::int8_t myInt{65};

myInt += 1;

std::cout << myInt;

}

Guess what this returns?

Character "B".

int main()

{

std::int8_t myInt{};

std::cin >> myInt;

std::cout << myInt;

}

This will also read a character, and

print the characters ascii value.

So if I give it 35, it read it only first '3', and prints out 51.

The g++ 13.2 compiler gives also no warning of this whatsoever with the flags:

                "-std=c++20",
                "-pedantic-errors",
                "-Wall",
                "-Wpedantic",
                "-Wshadow",
                "-Wcast-align",
                "-Wlogical-op",
                "-Wno-unused-parameter",
                "-Weffc++",
                "-Wextra",
                "-Wconversion",
                "-Wsign-conversion".

It does seem like a mistake to have `signed char` and `unsigned char` display as characters rather than numbers, since `char` is a distinct type. And so `char` could display as a character and the other two as integers.

Wish you can change this, or at least have a warning, because <iostream> functions fine for higher bitted integers.

Thanks.

OE