Hi

On 19 December 2022 14:32:32 GMT, Vladimir Grigoriev via Std-Discussion <std-discussion_at_[hidden]> wrote:
>
>There is another unclear phrase in the C++ 20 Standard relative to comparison operators.
>
>«3 The return value V of a defaulted == operator function with parameters x and y is determined by comparing corresponding elements xi and yi in the expanded lists of subobjects for x and y (in increasing index order) until the first index i where xi == yi yields a result value which, when contextually converted to bool, yields false. If no such index exists, V is true. Otherwise, V is false.»
>
>What does the last statement « Otherwise, V is false.»» mean?

My reading in pseudocode it would look something like:

/* ...comparing corresponding elements xi and yi in the expanded lists of subobjects for x and y (in increasing index order) until the first index i where xi == yi yields a result value which, when contextually converted to bool, yields false. */
bool mismatch_found = false;
for (size_t idx=0; idx < member_count; ++idx) {
    if (not (lhs_members[idx] == rhs_members[idx]) {
        mismatch_found = true;
        break;
    }
}

// If no such index exists, ...
if (not mismatch_found) {
    return true; // ... V is true.
} else { // Otherwise, ...
    return false; // ... V is false.
}

The first part describes the side effects of the defaulted definition, and the short-circuiting in particular. The second part describes the returned value.

Obviously this can be written more clearly and concisely in pseudocode. Would be nice if it could similarly be simplified in English.

Cheers,
Lénárd