Date: Fri, 21 Oct 2022 13:36:57 +0200
HI all,
the standard explicitly makes this exception: accessing an inactive
union member is not UB if the members are structs with initial common
sequence.
Is this also true in a constexpr context? I ask this because the chapter
for constexpr expression does not mention this exception accessing an
inactive memeber.
Here is some test-code:
struct A {
char e0;
};
struct B {
char e0;
};
template<typename A, typename B>
union U {
A a;
B b;
};
int main() {
constexpr U<A, B> u{.a = {1}}; // sets member a active
constexpr char t1 = u.b.e0; // should be ok, because read via a
struct with common initial sequence, but also in a constexpr context?
}
the standard explicitly makes this exception: accessing an inactive
union member is not UB if the members are structs with initial common
sequence.
Is this also true in a constexpr context? I ask this because the chapter
for constexpr expression does not mention this exception accessing an
inactive memeber.
Here is some test-code:
struct A {
char e0;
};
struct B {
char e0;
};
template<typename A, typename B>
union U {
A a;
B b;
};
int main() {
constexpr U<A, B> u{.a = {1}}; // sets member a active
constexpr char t1 = u.b.e0; // should be ok, because read via a
struct with common initial sequence, but also in a constexpr context?
}
-- Wilhelm
Received on 2022-10-21 11:36:59