I made a typo. I meant
 
namespace N1::N3
{i
 int x = i + j;
}
 
 
You can meet me at http://cpp.forum24.ru/ or www.stackoverflow.com or http://ru.stackoverflow.com
 
  
>Четверг, 28 мая 2020, 3:24 +03:00 от Vladimir Grigoriev via Std-Discussion <std-discussion_at_[hidden]>:
>
>It seems I have understood the quote. The quote menas that the shown program is equivalent to the following
>
>#include <iostream>
>
>namespace N1
>{
> namespace N2
> {
> int i = 10;
> }
> using namespace N2;
> namespace N3
>    {
>        extern int x;
>    }
>    inline namespace N4
>    {
>        int j = 20;
> }
>}
>
>int i = 1;
>int j = 2;
>namespace N1::N3
>{i
>x = i + j;
>}
>int main()
>{
> std::cout << "N1::N3::x = " << N1::N3::x << '\n';
>}
>
>
>
>
>You can meet me at http://cpp.forum24.ru/ or www.stackoverflow.com or http://ru.stackoverflow.com
>
>
>>Четверг, 28 мая 2020, 3:06 +03:00 от Vladimir Grigoriev via Std-Discussion < std-discussion_at_[hidden] >:
>>
>>According to the C++ 20 Standard (6.5.1 Unqualified name lookup)
>>
>>14 If a variable member of a namespace is defined outside of the scope of its namespace then any name that appears in the definition of the member (after the declarator-id) is looked up as if the definition of the member occurred in its namespace.
>>
>>Now let’s consider the following program
>>
>>#include <iostream>
>>
>>namespace N1
>>{
>> namespace N2
>> {
>> int i = 10;
>> }
>> using namespace N2;
>> namespace N3
>> {
>> extern int x;
>> }
>> inline namespace N4
>> {
>> int j = 20;
>> }
>>}
>>
>>int i = 1;
>>int j = 2;
>>int N1::N3::x = i + j;
>>
>>int main()
>>{
>> std::cout << "N1::N3::x = " << N1::N3::x << '\n';
>>}
>>
>>The MS Visual C++ 2019 produces the following result
>>
>>N1::N3::x = 30
>>
>>So several questions arise. The first one is the program valid? That is are the variable declarations
>>
>>int i = 1;
>>int j = 2;
>>
>>are visible in the this declaration
>>
>>int N1::N3::x = i + j;
>>?
>>
>>That is if the definition «occurs» in the namespace (according to the quote) then the names are not visible. If I am wrong then should the value of the variable x be equal to 12? Is it a bug of the compiler that outputs the value of x equal to 30?
>>
>>With best regards,
>>(Vlad from Moscow)
>>
>>You can meet me at http://cpp.forum24.ru/ or www.stackoverflow.com or http://ru.stackoverflow.com
>>--
>>Std-Discussion mailing list
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>>https://lists.isocpp.org/mailman/listinfo.cgi/std-discussion
>>
>
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