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Subject: Re: Rationale for return type of the non-array version of std::ssize()
From: Gennaro Prota (gennaro.prota_at_[hidden])
Date: 2020-05-12 03:09:11


On Mon, May 11, 2020 at 4:30 PM Thiago Macieira <thiago_at_[hidden]> wrote:
>
> On Monday, 11 May 2020 03:56:18 PDT Gennaro Prota wrote:
> > > Or on some exotic platform with small size_t and ptrdiff_t.. ptrdiff_t is
> > > not required to work for any two arbitrary pointers, only those of one
> > > memory block. [...]
> >
> > Thanks, and sorry for the late reply. OK, so I think the next question
> > is: why not just returning std::make_signed_t< decltype( c.size() ) >?
>
> Same answer: size_t may not be big enough for this particular container.
> size_t only needs to be big enough to hold the biggest object in memory.

Yes, so the container's size() member won't return a size_t.

--
--
.:: Gennaro Prota ::.
.:: https://about.me/gennaro.prota ::.

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