I can’t figure out what the password is, someone help me please.

It refers to “the old one” but I have no idea where to look for that.

Thanks,
Timur

> On 1 Apr 2022, at 12:18, Aaron Ballman <compatibility.sg.chair_at_[hidden]> wrote:
>
> Reminder: the SG22 meeting is happening today, in just under four
> hours from now, at 15:00 UTC
> (https://www.timeanddate.com/worldclock/converter.html?iso=20220401T150000&p1=tz_pt&p2=tz_mt&p3=tz_ct&p4=tz_et&p5=1440).
>
> See the agenda below for more details.
>
> ~Aaron
>
> On Fri, Mar 18, 2022 at 10:07 AM Aaron Ballman
> <compatibility.sg.chair_at_[hidden]> wrote:
>>
>> Our next meeting will be on Fri Apr 1, 2022 at 15:00 UTC
>> (https://www.timeanddate.com/worldclock/converter.html?iso=20220401T150000&p1=tz_pt&p2=tz_mt&p3=tz_ct&p4=tz_et&p5=1440).
>>
>> **NEW TIME: this meeting is being held at our new scheduled time which
>> is two hours earlier than previous meetings.**
>>
>> You can join the meeting at https://iso.zoom.us/j/5513145100
>>
>> **NEW PASSWORD: same as the old one, but spelled as a C reserved
>> identifier instead of a C++ keyword; contact Aaron Ballman if you have
>> questions.**
>>
>> We will be discussing the following papers:
>>
>> P2552R0 (https://wg21.link/p2552r0) On the ignorability of standard attributes
>> Discusses the circumstances under which it should be permissible to
>> ignore a standards-defined attribute and what "ignore" actually means
>> in terms of program semantics. The proposal attempts to remain in line
>> with the wording already in the C standard, but with a possibly more
>> precise specification.
>>
>> P2174R0 (https://wg21.link/p2174r0) Compound Literals
>> This paper proposes to introduce the C99 compound literal feature into
>> C++, as there is significant, yet diverging, existing practice amongst
>> C++ compilers to support this feature. The paper calls out some
>> differences between the feature in C and the feature in C++.
>>
>> There is a possibility we will also be discussing P2142R1
>> (https://wg21.link/p2142r1) Allow '.' operator to work on pointers,
>> but I have not yet heard back whether the author is available. If they
>> are, I will amend the agenda accordingly.
>>
>> Thanks!
>>
>> ~Aaron